Lesson 6.1: The "Other Way" - Risk-Neutral Valuation

Welcome to Module 6. We have successfully derived the Black-Scholes-Merton PDE and used its solution to understand the 'Greeks.' Our derivation (in Module 4) was the 'classic' 1973 method.

  1. Build a portfolio Π=V+ΔSt\Pi = -V + \Delta S_t.
  2. Apply Itô's Lemma to dΠd\Pi.
  3. Choose Δ\Delta to "kill" the random dWtdW_t term.
  4. Show that the subjective drift μ\mu "magically" canceled out.
  5. Argue that this risk-free portfolio must earn the risk-free rate rr.
  6. This left us with a complex Partial Differential Equation (PDE) to solve.

This method is brilliant, but it's very difficult. What if the option is complex? What if we have multiple random factors? This "delta-hedging" method becomes a nightmare.

This lesson is about a different way to get the same answer. It's a "shortcut" that is more powerful, more intuitive, and the foundation of all modern quant finance. This is Risk-Neutral Valuation.

Part 1: The "Real World" vs. The "Risk-Neutral World"

This is a "thought experiment." We need to understand the two "worlds" we can live in.

World 1: The "Real World" (Physical Measure P\mathbb{P})

This is the world we live in, the world that news anchors report on.

  • Investors are "Risk-Averse": We don't like risk. If a safe government bond pays 5%, we would *not* buy a risky stock unless we *expected* it to make more (e.g., 8% or 10%).
  • The Drift μ\mu: The stock's expected return μ\mu is subjective (my guess is different from yours) and greater than rr (μ>r\mu > r).
  • The SDE (Our GBM Model):
    dSt=μStdt+σStdWtPdS_t = \mu S_t dt + \sigma S_t dW_t^{\mathbb{P}}
    (We use WtPW_t^{\mathbb{P}} to show this is a "real-world" random walk).

The Problem: We can't use this SDE to price an option, because we can't agree on what μ\mu is.

World 2: The "Magic" Risk-Neutral World (Measure Q\mathbb{Q})

Now, let's *imagine* a parallel universe. In this "magic" world, all investors are "risk-neutral."

  • Investors are "Risk-Neutral": They *do not care* about risk. A 5% return from a risky stock is just as good as a 5% return from a safe bond.
  • The Drift rr: In this world, investors don't need to be "bribed" with a higher return to take on risk. Therefore, **every single asset** (stocks, bonds, etc.) must have an expected return exactly equal to the risk-free rate, rr.
  • The SDE (The "Magic" SDE):
    dSt=rStdt+σStdWtQdS_t = r S_t dt + \sigma S_t dW_t^{\mathbb{Q}}
    (Note: The volatility σ\sigma is the *same*! But the drift is now rr, and the random path dWtQdW_t^{\mathbb{Q}} is a different "magic world" path).

Part 2: The "Aha!" Moment (Why Are We Allowed to Do This?)

This seems like a silly "thought experiment." Why are we allowed to just "jump" into a "magic world" where μ=r\mu=r?

Because our PDE derivation in Module 4 *proved* it's allowed!

Remember the two "magic tricks" from Lessons 4.2 and 4.3?

  1. We "killed" the random dWtdW_t term by choosing Δ=VS\Delta = \frac{\partial V}{\partial S}.
  2. When we did that, the μ\mu term **canceled out completely**.

Our final Black-Scholes-Merton PDE...

Vt+rStVS+12σ2St22VS2rV=0\frac{\partial V}{\partial t} + \mathbf{r} S_t \frac{\partial V}{\partial S} + \frac{1}{2}\sigma^2 S_t^2 \frac{\partial^2 V}{\partial S^2} - \mathbf{r}V = 0

...**does not contain μ\mu anywhere.**

The price of an option is independent of the stock's expected return μ\mu.

This means that we will get the **exact same price** for the option whether we do our calculation in the "real world" (using μ=10%\mu=10\%) or in the "magic world" (using μ=5%\mu=5\%).

So, if we're *guaranteed* to get the same answer, why not just *pretend* we live in the "magic" risk-neutral world from the start? The math becomes *infinitely* easier. We just set μ=r\mu = r and solve the problem.

Part 3: The New Pricing Formula (The "Shortcut")

This "magic world" gives us a powerful new way to price derivatives, known as the Fundamental Theorem of Asset Pricing.

It states that in a "no-free-lunch" (no-arbitrage) market, the fair price of any derivative (VV) today is simply:

"The expected payoff of the derivative at expiration, calculated in the 'risk-neutral world' (where μ=r\mu=r), and then discounted back to today using the risk-free rate rr."

The Risk-Neutral Valuation Formula ("The Shortcut")

V(t)=EQ[er(Tt)Payoff(ST)]V(t) = \mathbb{E}^{\mathbb{Q}} \left[ e^{-r(T-t)} \cdot \text{Payoff}(S_T) \right]

Let's translate this:

  • V(t)V(t): The option's fair price today.
  • EQ[]\mathbb{E}^{\mathbb{Q}}[\dots]: The "Expected Value" (the average payoff) calculated in our **"magic" Q\mathbb{Q} world**.
  • er(Tt)e^{-r(T-t)}: The "Present Value" discount factor (from Lesson 0.1).
  • Payoff(ST)\text{Payoff}(S_T): The option's payoff at expiration (time TT).

Part 4: A Concrete Example (Call Option)

Let's see how this "shortcut" gets us the Black-Scholes formula.

Problem: Price a Call Option, where Payoff=max(STK,0)\text{Payoff} = \max(S_T - K, 0).

  • Old Way (PDE Method): We must solve this complex PDE from Module 4:
    Vt+rStVS+12σ2St22VS2rV=0\frac{\partial V}{\partial t} + r S_t \frac{\partial V}{\partial S} + \frac{1}{2}\sigma^2 S_t^2 \frac{\partial^2 V}{\partial S^2} - rV = 0
    This is a "pure math" problem that is very difficult.
  • New Way (Risk-Neutral Method): We just solve this statistics problem:
    C=er(Tt)EQ[max(STK,0)]C = e^{-r(T-t)} \cdot \mathbb{E}^{\mathbb{Q}}[ \max(S_T - K, 0) ]
    To solve this, we just need to know the statistics of STS_T in our "magic world." In Lesson 3.4, we'll (optionally) show that the *solution* to our "magic" SDE (dSt=rStdt+dS_t = r S_t dt + \dots) is:
    ST=Stexp((r12σ2)(Tt)+σWTQ)S_T = S_t \exp\left( (r - \frac{1}{2}\sigma^2)(T-t) + \sigma W_T^{\mathbb{Q}} \right)
    This is a log-normal distribution.

When you (or rather, a PhD-level statistician) calculate the "expected value" of a log-normal distribution, the answer that pops out is *exactly* the Black-Scholes formula:

EQ[max(STK,0)]=Ster(Tt)N(d1)KN(d2)\mathbb{E}^{\mathbb{Q}}[ \max(S_T - K, 0) ] = S_t e^{r(T-t)} N(d_1) - K N(d_2)

Now, plug this into our "Shortcut" formula and multiply by er(Tt)e^{-r(T-t)}:

C=er(Tt)[Ster(Tt)N(d1)KN(d2)]C = e^{-r(T-t)} \left[ S_t e^{r(T-t)} N(d_1) - K N(d_2) \right]
C=StN(d1)Ker(Tt)N(d2)C = S_t N(d_1) - K e^{-r(T-t)} N(d_2)

We get the *exact same answer* as the PDE method, but with statistics instead of a complex PDE.

Up Next: Lesson 6.2: The "Computer Way" - Monte Carlo Methods